题目：
读入一个自然数n，计算其各位数字之和，用汉语拼音写出和的每一位数字。
输入格式：每个测试输入包含1个测试用例，即给出自然数n的值。这里保证n小于10100。
输出格式：在一行内输出n的各位数字之和的每一位，拼音数字间有1 空格，但一行中最后一个拼音数字后没有空格。
输入样例：
1234567890987654321123456789
输出样例：
yi san wu 题目较简单，也不用判断输入的格式是否正确。代码如下(java)：
1 import java.io.*; 2 import java.util.*; 3 public class Main 4 { 5 public static void main(String args[]){ 6 Scanner cin = new Scanner(System.in); 7 while(cin.hasNext()){ 8 String inputString = cin.next(); 9 int sum = 0;10 for(int i = 0;i < inputString.length();i++){11 sum += Integer.parseInt(inputString.substring(i, i+1));12 }13 System.out.println(toString(sum));14 }15 }16 public static String toString(int n){17 String output = new String();18 String s = Integer.toString(n);19 for(int i = 0;i < s.length();i++){20 if('0' == s.charAt(i) && i != 0)21 output += " " + "ling";22 else if('1' == s.charAt(i)){23 if(0 == i)24 output += "yi";25 else 26 output += " " + "yi";27 }28 else if('2' == s.charAt(i)){29 if(0 == i)30 output += "er";31 else 32 output += " " + "er";33 }34 35 else if('3' == s.charAt(i)){36 if(0 == i)37 output += "san";38 else 39 output += " " + "san";40 }41 42 else if('4' == s.charAt(i)){43 if(0 == i)44 output += "si";45 else 46 output += " " + "si"; 47 }48 49 else if('5' == s.charAt(i)){50 if(0 == i)51 output += "wu";52 else 53 output += " " + "wu";54 }55 else if('6' == s.charAt(i)){56 if(0 == i)57 output += "liu";58 else 59 output += " " + "liu";60 }61 62 else if('7' == s.charAt(i)){63 if(0 == i)64 output += "qi";65 else66 output += " " + "qi";67 }68 69 else if('8' == s.charAt(i)){70 if(0 == i)71 output += "ba";72 else73 output += " " + "ba";74 }75 76 else if('9' == s.charAt(i)){77 if(0 == i)78 output += "jiu";79 else 80 output += " " + "jiu"; 81 }82 83 }84 return output;85 86 87 }88 }